Volume of a Sphere
Volume
of a sphere is the total space occupied by the sphere.
To derive the formula for the volume of a sphere we can do the following
activity:
- Take
a cylindrical vessel circumscribing a plastic spherical ball as given in the
figure above.
- Take
out the spherical ball from the cylinder and cut it into two equal parts. In
this way we will get two hemispheres of plastic ball.
- Fill
a hemisphere with rice or sand and pour it into the cylinder. And repeat it again.
- Then
we will find that the cylinder will be full filled by 3 hemispheres.
Thus, the volume of 3 hemisphere = volume of 1 cylinder
= πr2 × d [∵ h = d]
= πr2 × 2r [∵ d = 2r]
= 2πr3
∴ Volume of 1 hemisphere
= 2πr3/3
Thus, the volume of a hemisphere = 2πr3/3
Now,
The volume of a sphere = volume of two hemispheres
=
2 × 2πr3/3
= 4πr3/3
∴ The
volume of a sphere = 4πr3/3
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Workout Examples
Example 1: Find the volume of a sphere of radius 21cm.
Solution: Here, radius of
sphere (r) = 21cm
Now,
Volume
of sphere = 4πr3/3
= 4/3 × 22/7 × (21)3
= 38808cm3
Thus,
the volume of sphere is 38808cm3.
Example 2: Three metallic spheres each of diameters 1cm, 6cm and 8cm
are melted to form a single sphere. Find the radius of single sphere.
Solution: Here, radii of three
spheres are,
r1
= 1cm
r2
= 6cm
r3
= 8cm
Therefore,
volumes of three spheres are,
v1
= 4πr3/3 = 4/3 × 22/7 × (1)3 = 4.19cm3
v2
= 4πr3/3 = 4/3 × 22/7 × (6)3 = 905.14cm3
v3
= 4πr3/3 = 4/3 × 22/7 × (8)3 = 2145.52cm3
Three spheres are
melted to form a single sphere, therefore,
The volume
of single sphere = v1 + v2 + v3
i.e. 4πr3/3 = 4.19 + 905.14 + 2145.52
or, 4/3 × 22/7 × r3 = 3054.85
or, r3 = 3054.85 × 21/88
or r3 = 729
or, r 3 = 93
or, r = 9cm
Thus,
the radius of single sphere is 9cm.
You can comment your questions or problems
regarding the volume of sphere here.
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