Mean Deviation
Mean deviation or average deviation is
defined as the arithmetic mean of the deviations of the items from mean or
median or mode. Since median is the central point of any distribution, mean
deviation from median generally gives the best result among the average
deviations. Since mode is ill defined, mean deviation from mode will generally
be not used.
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Individual Series:
In case of individual series, mean
deviation is calculated as follows:
Where A = mean or median or mode and |x – A| is
modulus or absolute value of x – A. That is magnitude of (x – A) or value of
deviation taken from average A ignoring the negative sign.
Discrete and Continuous Series:
In case of discrete and continuous series the mean
deviation can be calculated by the formula,
In case of continuous distribution, x is taken as
the mid-point of corresponding class.
Coefficient of Mean Deviation
The coefficient of mean deviation is given by the
formula,
Where A is the average from which the mean
deviation is calculated.
Workout Examples
Example 1: Calculate the mean deviation
and its coefficient from mean and median of the following series.
24, 28, 29, 33, 36, 35, 25
Solution: Here,
Arranging the data in
ascending order,
Data: 24, 25, 28, 29,
33, 35, 36
No. of data (N) = 7
Calculation
of Mean Deviation
M.D. from mean
|
M.D. from median
|
||||
x
|
x – A
|
|x – A|
|
x
|
x – A
|
|x – A|
|
24
25
28
29
33
35
36
|
-6
-5
-2
-1
3
5
6
|
6
5
2
1
3
5
6
|
24
25
28
29
33
35
36
|
-5
-4
-1
0
4
6
7
|
5
4
1
0
4
6
7
|
∑|x – A| = 28
|
∑|x – A| = 27
|
Now,
Example 2: Calculate the mean deviation
from median of the following frequency table. Also find its coefficient.
Height (cm)
|
10
|
20
|
30
|
40
|
50
|
60
|
No. of plants
|
2
|
3
|
9
|
21
|
11
|
5
|
Solution: Here,
Calculation
of Mean Deviation
x
|
f
|
cf
|
|x – A|
|
f|x – A|
|
10
20
30
40
50
60
|
2
3
9
21
11
5
|
2
5
14
35
46
51
|
30
20
10
0
10
20
|
60
60
90
0
110
100
|
N = 51
|
420
|
Now,
No. of data (N) = 51
Hence, mean deviation from median is
8.235 and its coefficient is 0.205.
Example 3: Find the mean deviation from mean
and its coefficient.
Marks
|
10-20
|
20-30
|
30-40
|
40-50
|
50-60
|
60-70
|
70-80
|
No. of Students
|
4
|
7
|
9
|
18
|
12
|
7
|
3
|
Solution: Here,
Marks
|
Frequency (f)
|
Mid-value (x)
|
fx
|
|x – A|
|
f|x – A|
|
10-20
20-30
30-40
40-50
50-60
60-70
70-80
|
4
7
9
18
12
7
3
|
15
25
35
45
55
65
75
|
60
175
315
810
660
455
225
|
30
20
10
0
10
20
30
|
120
140
90
0
120
140
90
|
N = 60
|
2700
|
700
|
Here, total no. of data (N) = 60
Hence, mean deviation = 11.667 and
its coefficient = 0.259.
You can comment your
questions or problems regarding mean deviation here.
what the heck is this mix do mean and median separately
ReplyDeletedont use unparliamentary language in an official website
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