
Quartiles
For the quartile deviation, let us have an idea about the quartiles. We know that the median
divides the given observations arranged in ascending or descending order into
two equal parts. Similarly, the quartiles divide the given observations into
four equal parts after arranging them in ascending or descending order. So
there are three quartiles denoted by Q1, Q2 and Q3
known as the first, the second and the third quartile respectively.
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If N be the number of observations of discrete data arranged in the ascending or descending order, then the quartiles are given by the following formula:

In the case of continuous frequency distribution, the quartiles are calculated by the following formula:

Inter Quartiles Range
Inter Quartile Range: The difference between the
third and the first quartile is called inter
quartile range.
i.e. Inter Quartile Range = Q3 – Q1
Quartiles Deviations
The average
of deviation of the first quartile and the third quartile taken from median (M)
is called the quartile deviation or semi-inter quartile range.

Coefficient of Quartiles
As the unit of quartile deviation is same as that of the given
observations, the two distributions with different units cannot be compared by
quartile deviation. To facilitate the comparison of the quartiles of two or
more than two series, a relative measure, the coefficient of quartile deviation is used, which is calculated as,

Worked Out Examples



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calculate lower and upper quartiles, when quartile deviation =10 and co-efficient of quartile deviation=0.5
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Less than30 5 30-40 4 40-50 3 50-60 3 60-70 5 find quartile deviation
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Comment here if you have more problems regarding the quartile deviation.
length in hours:700-900 900-100 1100-1300 1300-1500
ReplyDeletesamples: 10 16 26 8
find out standard deviation by step deviation method
Calculation of Standard Deviation by step-deviation method: [image src="https://blogger.googleusercontent.com/img/a/AVvXsEiZGHMpZWSgApdWNIe0fMnb3nOvmAhq8-U0gxqON9jZx9x9JKRnjjr5aSt9uIxANXU4TE2fz9QXoajPLYHyxEjbTua6dTilTVDTLFtZ4NGH-mfOwIiq84II3O6ESeQvj100F6zmlrgbpyxQ_Ky9uKZ9hJXD_7Hdsj642wpVowX3HOJLMKLL4oHX_Bc41Q=s16000 "/]
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Please do one question in which ci is given like 0 to 10. 0 to 20. 0 to 40.
ReplyDeleteWe have to change the class intervals into 0-10, 10-20, 20-30… and filter the frequency values accordingly and then find quartile deviation. You can post your question here.
DeleteIn symmetric distribution 50% of the items are above 60 and 75% of the items are below 75. Therefore, the coefficent of quartile is ---- and the coefficient of skewness is -----
ReplyDelete17,2,7,27,15,5,14,8,10,24,48,10,8,7,18,28 pls solve that problem
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