If A and B are two non-empty sets then the set of all possible
ordered pairs (x, y) such that the first component x is an element of A and the
second component y is an element of B is called the Cartesian Product of set A
and B. It is denoted by A × B which is read as “A cross B”.
In the set-builder form, we can write
A × B = {(a, b): a ∈ A, b ∈ B}
********************
10 Math Problems officially announces the release of Quick Math Solver and 10 Math Problems, Apps on Google Play Store for students around the world.
********************
********************
For example:
1.
If A = {a, b} and B = {1,
2} then, A × B = {(a, 1), (a, 2), (b, 1), (b, 2)} and B × A = {(1, a), (1, b),
(2, a), (2, b)}.
2.
If A = {1, 2, 3} and B =
{2, 4, 6} then, A × B = {(1, 2), (1, 4), (1, 6), (2, 2), (2, 4), (2, 6), (3,
2), (3, 4), (3, 6)} and B × A = {(2, 1), (2, 2), (2, 3), (4, 1), (4, 2), (4,
3), (6, 1), (6, 2), (6, 3)}.
3.
If A = {H, T} then A × A =
{(H, H), (H, T), (T, H), (T, T)}.
Note:
1.
A × B ≠ B × A.
2.
If m = number of elements
of A and n = number of elements of B, then the number of elements of A × B is
mn.
Representation of the Cartesian Product
If A = {1, 2, 3} and B = {1, 2} then the Cartesian Product A × B
can be represented as follows:
(a) Set of Ordered Pairs: A × B = {(1, 1), (1, 2), (2, 1,
(2, 2), (3, 1), (3, 2)}
(b) Lattice Diagram:
(c) Table:
(d) Mapping Diagram:
(e) Tree Diagram:
Worked Out Examples
Example 1: If A = {a, b} and B = {1, 2, 3} then find A × B.
Solution: Here, A = {a, b} and B = {1, 2, 3}
∴ A × B = {(a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3)}
Example 2: If A = {x ∈ N : x ≤ 4}, find A × A.
Solution: Here, A = {x ∈ N : x ≤ 4} ∴ A = {1, 2, 3, 4}
Now, from the above table
A × B = {(1, 1), (a, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3),
(2, 4), (3, 1), (3, 2), (3, 3), (3, 4), (4, 1), (4, 2), (4, 3), (4, 4)}
Example 3: Draw the arrow diagram of A × B and B × A if A = {a, b} and B = {x,
y, z}.
Solution: Here, A = {a, b} and B = {x, y, z}
A × B in mapping diagram
A × B = {(a, x), (a, y), (a, z), (b, x), (b, y), (b, z)}
B × A in mapping diagram
B × A = {(x, a), (x, b), (y, a), (y, b), (z, a), (z, b)}
0 comments: